Honestly, that is a very complicated way to represent a textual board. I would recommend, if possible, using an object-oriented approach, such as making the board into a list of lists, where every entry in the list is an list of strings that represents a row, with a __repr__ method to help visualize it more easily. Here is an example I wrote. Class Board(object): def __init__(self, rows, columns): self.rows = rows self.columns = columns self.board = [['_' for i in range(self.columns)] for i in range(self.rows)] def __repr__(self): board = ' for row in self.board: board += '.join(row) + ' n' return board f = Board(5, 5) =>None f =>_____ _____ _____ _____ _____ This way, a blank board is represented as a dual list-comprehension, where your rows parameter is the vertical length, and your columns parameter is the horizontal length. With this code, try writing a method to add a piece onto the board, by finding the lowest point in a column that isn't the opponents piece.

Hi, I am trying to write a connect four program in python, which I am not very experienced. This is what I have so far: [Code]. Connect Four Help. Creating a Connect 4 game in python but don't know where to begin. You have a 7x6 board, and you need to see if a line of 4 adjacent or diagonal spaces contain the. Connect Four Python. A guest Jan 24th, 2012 3,106 Never Not a member. Description: This is a connect four program that asks for user input on whether. S my connect 4 code that's for a 6x7 board. Import random def winner(board ): ''This function accepts the Connect 4 board as a parameter. Python Connect four.

Hello This is like my 4th week using Python and I'm still not familiar with it so I might need some help from you guys. I gotta write a little Connect 4 game in Python, I just got started and boom - I'm stuck! I tried to create a board for the game using two lists. Here is how far I got: def board(): fielda = [] fieldb = [] rows = int(raw_input('Height ')) columns = int(raw_input('Width ')) if rows. Wow, that was fast, thanks. It works perfectly but umm.

What does your code actually do? I don't get through it - any comments maybe? Denon Dct A100 Manual Lawn there. Well best way to understand it is to hand-execute it:) for row in fielda: for spot in row: print spot, print so, the first row in fielda is row = [ '-', '-', '-', '-', '-' ] going in the second loop: the first spot in it is '-', therefore it prints '-' and remains on the same line because of the ','( comma ) after the print statement.

So if loops over every '-' in the row and prints it. When it gets to the point that no more elements are left, exits the loop and uses 'print' to go to the next line of the output. Descargar La Traicion Telenovela Completa. Since there are no other statements in the body of the outer for loop, it continues to the second row and so on. Hope this makes it clearer:) Edited 8 Years Ago by masterofpuppets: messed up the tabs. I'm sorry, I didn't comment it because I saw you use some of the code in your project and just assumed things, but here's what it does.

Whenever you have for obj in container:, python does the for loop once for each obj that's in container. SomeList = [1,2,3] for i in range(3): print someList[i].is the same as. SomeList = [1,2,3] for num in someList: print num When I did for row in fielda:, that did the for loop once for each list inside the list fielda, and referred to that inner list as row.

When I did for spot in field:, that did the for loop once for each character inside the list row, and referred to that character as spot. Notice my names are intuitive. Download Free Sins Of The Solar Empire Patch Fr Software.